Remedial MTK

METODE  SUBTITUSI
(1). x+y= 1   =>          x+y=-1
     3x+2y= -2                  x=-1-y

        3x+2y=-2                      x=-1-y     
3(-1-y)+2y=-2                      x=-1-(-1)   
   -3-3y+2y=-2             à    x=-1+1
            -3-y=-2                     x=0
                -y=-2+3                       
                -y=1                       HP={0,-1}
                 y=-1          



METODE  ELIMINASI
(2).     x+y=-1     |3|
      3x+2y=-2      |1|

  3x+3y=-3
  3x+2y=-2                   à   3x+2y=-2
__________ -                   3+2(-1)=-2
           y=-1                              3x-2=-2
                                                    3x=-2+2            
                                                      x=0/3
                                                      x= 0
   HP={0,-1}